3.4.2 \(\int \frac {\cos ^{\frac {5}{2}}(a+b x)}{\sin ^{\frac {5}{2}}(a+b x)} \, dx\) [302]

3.4.2.1 Optimal result
3.4.2.2 Mathematica [C] (verified)
3.4.2.3 Rubi [A] (verified)
3.4.2.4 Maple [B] (verified)
3.4.2.5 Fricas [C] (verification not implemented)
3.4.2.6 Sympy [F(-1)]
3.4.2.7 Maxima [F]
3.4.2.8 Giac [F]
3.4.2.9 Mupad [B] (verification not implemented)

3.4.2.1 Optimal result

Integrand size = 21, antiderivative size = 201 \[ \int \frac {\cos ^{\frac {5}{2}}(a+b x)}{\sin ^{\frac {5}{2}}(a+b x)} \, dx=-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{\sqrt {2} b}+\frac {\arctan \left (1+\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{\sqrt {2} b}+\frac {\log \left (1+\cot (a+b x)-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{2 \sqrt {2} b}-\frac {\log \left (1+\cot (a+b x)+\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{2 \sqrt {2} b}-\frac {2 \cos ^{\frac {3}{2}}(a+b x)}{3 b \sin ^{\frac {3}{2}}(a+b x)} \]

output
-2/3*cos(b*x+a)^(3/2)/b/sin(b*x+a)^(3/2)+1/2*arctan(-1+2^(1/2)*cos(b*x+a)^ 
(1/2)/sin(b*x+a)^(1/2))/b*2^(1/2)+1/2*arctan(1+2^(1/2)*cos(b*x+a)^(1/2)/si 
n(b*x+a)^(1/2))/b*2^(1/2)+1/4*ln(1+cot(b*x+a)-2^(1/2)*cos(b*x+a)^(1/2)/sin 
(b*x+a)^(1/2))/b*2^(1/2)-1/4*ln(1+cot(b*x+a)+2^(1/2)*cos(b*x+a)^(1/2)/sin( 
b*x+a)^(1/2))/b*2^(1/2)
 
3.4.2.2 Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 0.03 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.28 \[ \int \frac {\cos ^{\frac {5}{2}}(a+b x)}{\sin ^{\frac {5}{2}}(a+b x)} \, dx=-\frac {2 \sqrt [4]{\cos ^2(a+b x)} \operatorname {Hypergeometric2F1}\left (-\frac {3}{4},-\frac {3}{4},\frac {1}{4},\sin ^2(a+b x)\right )}{3 b \sqrt {\cos (a+b x)} \sin ^{\frac {3}{2}}(a+b x)} \]

input
Integrate[Cos[a + b*x]^(5/2)/Sin[a + b*x]^(5/2),x]
 
output
(-2*(Cos[a + b*x]^2)^(1/4)*Hypergeometric2F1[-3/4, -3/4, 1/4, Sin[a + b*x] 
^2])/(3*b*Sqrt[Cos[a + b*x]]*Sin[a + b*x]^(3/2))
 
3.4.2.3 Rubi [A] (verified)

Time = 0.43 (sec) , antiderivative size = 205, normalized size of antiderivative = 1.02, number of steps used = 13, number of rules used = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.571, Rules used = {3042, 3047, 3042, 3055, 826, 1476, 1082, 217, 1479, 25, 27, 1103}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\cos ^{\frac {5}{2}}(a+b x)}{\sin ^{\frac {5}{2}}(a+b x)} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {\cos (a+b x)^{5/2}}{\sin (a+b x)^{5/2}}dx\)

\(\Big \downarrow \) 3047

\(\displaystyle -\int \frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}dx-\frac {2 \cos ^{\frac {3}{2}}(a+b x)}{3 b \sin ^{\frac {3}{2}}(a+b x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\int \frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}dx-\frac {2 \cos ^{\frac {3}{2}}(a+b x)}{3 b \sin ^{\frac {3}{2}}(a+b x)}\)

\(\Big \downarrow \) 3055

\(\displaystyle \frac {2 \int \frac {\cot (a+b x)}{\cot ^2(a+b x)+1}d\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}}{b}-\frac {2 \cos ^{\frac {3}{2}}(a+b x)}{3 b \sin ^{\frac {3}{2}}(a+b x)}\)

\(\Big \downarrow \) 826

\(\displaystyle \frac {2 \left (\frac {1}{2} \int \frac {\cot (a+b x)+1}{\cot ^2(a+b x)+1}d\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}-\frac {1}{2} \int \frac {1-\cot (a+b x)}{\cot ^2(a+b x)+1}d\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{b}-\frac {2 \cos ^{\frac {3}{2}}(a+b x)}{3 b \sin ^{\frac {3}{2}}(a+b x)}\)

\(\Big \downarrow \) 1476

\(\displaystyle \frac {2 \left (\frac {1}{2} \left (\frac {1}{2} \int \frac {1}{\cot (a+b x)-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1}d\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+\frac {1}{2} \int \frac {1}{\cot (a+b x)+\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1}d\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )-\frac {1}{2} \int \frac {1-\cot (a+b x)}{\cot ^2(a+b x)+1}d\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{b}-\frac {2 \cos ^{\frac {3}{2}}(a+b x)}{3 b \sin ^{\frac {3}{2}}(a+b x)}\)

\(\Big \downarrow \) 1082

\(\displaystyle \frac {2 \left (\frac {1}{2} \left (\frac {\int \frac {1}{-\cot (a+b x)-1}d\left (1-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{\sqrt {2}}-\frac {\int \frac {1}{-\cot (a+b x)-1}d\left (\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{\sqrt {2}}\right )-\frac {1}{2} \int \frac {1-\cot (a+b x)}{\cot ^2(a+b x)+1}d\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{b}-\frac {2 \cos ^{\frac {3}{2}}(a+b x)}{3 b \sin ^{\frac {3}{2}}(a+b x)}\)

\(\Big \downarrow \) 217

\(\displaystyle \frac {2 \left (\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{\sqrt {2}}\right )-\frac {1}{2} \int \frac {1-\cot (a+b x)}{\cot ^2(a+b x)+1}d\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{b}-\frac {2 \cos ^{\frac {3}{2}}(a+b x)}{3 b \sin ^{\frac {3}{2}}(a+b x)}\)

\(\Big \downarrow \) 1479

\(\displaystyle \frac {2 \left (\frac {1}{2} \left (\frac {\int -\frac {\sqrt {2}-\frac {2 \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}}{\cot (a+b x)-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1}d\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}}{2 \sqrt {2}}+\frac {\int -\frac {\sqrt {2} \left (\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{\cot (a+b x)+\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1}d\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{\sqrt {2}}\right )\right )}{b}-\frac {2 \cos ^{\frac {3}{2}}(a+b x)}{3 b \sin ^{\frac {3}{2}}(a+b x)}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {2 \left (\frac {1}{2} \left (-\frac {\int \frac {\sqrt {2}-\frac {2 \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}}{\cot (a+b x)-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1}d\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}}{2 \sqrt {2}}-\frac {\int \frac {\sqrt {2} \left (\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{\cot (a+b x)+\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1}d\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{\sqrt {2}}\right )\right )}{b}-\frac {2 \cos ^{\frac {3}{2}}(a+b x)}{3 b \sin ^{\frac {3}{2}}(a+b x)}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {2 \left (\frac {1}{2} \left (-\frac {\int \frac {\sqrt {2}-\frac {2 \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}}{\cot (a+b x)-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1}d\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}}{2 \sqrt {2}}-\frac {1}{2} \int \frac {\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1}{\cot (a+b x)+\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1}d\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{\sqrt {2}}\right )\right )}{b}-\frac {2 \cos ^{\frac {3}{2}}(a+b x)}{3 b \sin ^{\frac {3}{2}}(a+b x)}\)

\(\Big \downarrow \) 1103

\(\displaystyle \frac {2 \left (\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{\sqrt {2}}\right )+\frac {1}{2} \left (\frac {\log \left (\cot (a+b x)-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\cot (a+b x)+\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{2 \sqrt {2}}\right )\right )}{b}-\frac {2 \cos ^{\frac {3}{2}}(a+b x)}{3 b \sin ^{\frac {3}{2}}(a+b x)}\)

input
Int[Cos[a + b*x]^(5/2)/Sin[a + b*x]^(5/2),x]
 
output
(2*((-(ArcTan[1 - (Sqrt[2]*Sqrt[Cos[a + b*x]])/Sqrt[Sin[a + b*x]]]/Sqrt[2] 
) + ArcTan[1 + (Sqrt[2]*Sqrt[Cos[a + b*x]])/Sqrt[Sin[a + b*x]]]/Sqrt[2])/2 
 + (Log[1 + Cot[a + b*x] - (Sqrt[2]*Sqrt[Cos[a + b*x]])/Sqrt[Sin[a + b*x]] 
]/(2*Sqrt[2]) - Log[1 + Cot[a + b*x] + (Sqrt[2]*Sqrt[Cos[a + b*x]])/Sqrt[S 
in[a + b*x]]]/(2*Sqrt[2]))/2))/b - (2*Cos[a + b*x]^(3/2))/(3*b*Sin[a + b*x 
]^(3/2))
 

3.4.2.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 217
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 826
Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 
2]], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*s)   Int[(r + s*x^2)/(a + b*x^ 
4), x], x] - Simp[1/(2*s)   Int[(r - s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{ 
a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] 
 && AtomQ[SplitProduct[SumBaseQ, b]]))
 

rule 1082
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 1103
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1476
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
2*(d/e), 2]}, Simp[e/(2*c)   Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ 
e/(2*c)   Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] 
 && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
 

rule 1479
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
-2*(d/e), 2]}, Simp[e/(2*c*q)   Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], 
 x] + Simp[e/(2*c*q)   Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F 
reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3047
Int[(cos[(e_.) + (f_.)*(x_)]*(a_.))^(m_)*((b_.)*sin[(e_.) + (f_.)*(x_)])^(n 
_), x_Symbol] :> Simp[a*(a*Cos[e + f*x])^(m - 1)*((b*Sin[e + f*x])^(n + 1)/ 
(b*f*(n + 1))), x] + Simp[a^2*((m - 1)/(b^2*(n + 1)))   Int[(a*Cos[e + f*x] 
)^(m - 2)*(b*Sin[e + f*x])^(n + 2), x], x] /; FreeQ[{a, b, e, f}, x] && GtQ 
[m, 1] && LtQ[n, -1] && (IntegersQ[2*m, 2*n] || EqQ[m + n, 0])
 

rule 3055
Int[(cos[(e_.) + (f_.)*(x_)]*(a_.))^(m_)*((b_.)*sin[(e_.) + (f_.)*(x_)])^(n 
_), x_Symbol] :> With[{k = Denominator[m]}, Simp[(-k)*a*(b/f)   Subst[Int[x 
^(k*(m + 1) - 1)/(a^2 + b^2*x^(2*k)), x], x, (a*Cos[e + f*x])^(1/k)/(b*Sin[ 
e + f*x])^(1/k)], x]] /; FreeQ[{a, b, e, f}, x] && EqQ[m + n, 0] && GtQ[m, 
0] && LtQ[m, 1]
 
3.4.2.4 Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(736\) vs. \(2(159)=318\).

Time = 4.13 (sec) , antiderivative size = 737, normalized size of antiderivative = 3.67

method result size
default \(\frac {\sqrt {2}\, \left (1-\cos \left (b x +a \right )\right ) \left (-\frac {\left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )-1}{\left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )+1}\right )^{\frac {5}{2}} \left (2 \sqrt {-\left (1-\cos \left (b x +a \right )\right ) \left (\left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )-1\right ) \csc \left (b x +a \right )}\, \left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )-3 \ln \left (\frac {-\left (1-\cos \left (b x +a \right )\right )^{2} \csc \left (b x +a \right )+2 \sqrt {-\left (1-\cos \left (b x +a \right )\right ) \left (\left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )-1\right ) \csc \left (b x +a \right )}\, \sin \left (b x +a \right )+2-2 \cos \left (b x +a \right )+\sin \left (b x +a \right )}{1-\cos \left (b x +a \right )}\right ) \left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )+6 \arctan \left (\frac {\sqrt {-\left (1-\cos \left (b x +a \right )\right ) \left (\left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )-1\right ) \csc \left (b x +a \right )}\, \sin \left (b x +a \right )+1-\cos \left (b x +a \right )}{1-\cos \left (b x +a \right )}\right ) \left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )+3 \ln \left (-\frac {\left (1-\cos \left (b x +a \right )\right )^{2} \csc \left (b x +a \right )+2 \sqrt {-\left (1-\cos \left (b x +a \right )\right ) \left (\left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )-1\right ) \csc \left (b x +a \right )}\, \sin \left (b x +a \right )-2+2 \cos \left (b x +a \right )-\sin \left (b x +a \right )}{1-\cos \left (b x +a \right )}\right ) \left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )+6 \arctan \left (\frac {\sqrt {-\left (1-\cos \left (b x +a \right )\right ) \left (\left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )-1\right ) \csc \left (b x +a \right )}\, \sin \left (b x +a \right )+\cos \left (b x +a \right )-1}{1-\cos \left (b x +a \right )}\right ) \left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )-2 \sqrt {-\left (1-\cos \left (b x +a \right )\right ) \left (\left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )-1\right ) \csc \left (b x +a \right )}\right ) \csc \left (b x +a \right )}{12 b \left (\frac {\csc \left (b x +a \right )-\cot \left (b x +a \right )}{\left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )+1}\right )^{\frac {5}{2}} \left (\left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )-1\right )^{2} \sqrt {-\left (1-\cos \left (b x +a \right )\right ) \left (\left (1-\cos \left (b x +a \right )\right )^{2} \left (\csc ^{2}\left (b x +a \right )\right )-1\right ) \csc \left (b x +a \right )}}\) \(737\)

input
int(cos(b*x+a)^(5/2)/sin(b*x+a)^(5/2),x,method=_RETURNVERBOSE)
 
output
1/12/b*2^(1/2)/(1/((1-cos(b*x+a))^2*csc(b*x+a)^2+1)*(csc(b*x+a)-cot(b*x+a) 
))^(5/2)*(1-cos(b*x+a))*(-((1-cos(b*x+a))^2*csc(b*x+a)^2-1)/((1-cos(b*x+a) 
)^2*csc(b*x+a)^2+1))^(5/2)*(2*(-(1-cos(b*x+a))*((1-cos(b*x+a))^2*csc(b*x+a 
)^2-1)*csc(b*x+a))^(1/2)*(1-cos(b*x+a))^2*csc(b*x+a)^2-3*ln(1/(1-cos(b*x+a 
))*(-(1-cos(b*x+a))^2*csc(b*x+a)+2*(-(1-cos(b*x+a))*((1-cos(b*x+a))^2*csc( 
b*x+a)^2-1)*csc(b*x+a))^(1/2)*sin(b*x+a)+2-2*cos(b*x+a)+sin(b*x+a)))*(1-co 
s(b*x+a))^2*csc(b*x+a)^2+6*arctan(1/(1-cos(b*x+a))*((-(1-cos(b*x+a))*((1-c 
os(b*x+a))^2*csc(b*x+a)^2-1)*csc(b*x+a))^(1/2)*sin(b*x+a)+1-cos(b*x+a)))*( 
1-cos(b*x+a))^2*csc(b*x+a)^2+3*ln(-1/(1-cos(b*x+a))*((1-cos(b*x+a))^2*csc( 
b*x+a)+2*(-(1-cos(b*x+a))*((1-cos(b*x+a))^2*csc(b*x+a)^2-1)*csc(b*x+a))^(1 
/2)*sin(b*x+a)-2+2*cos(b*x+a)-sin(b*x+a)))*(1-cos(b*x+a))^2*csc(b*x+a)^2+6 
*arctan(1/(1-cos(b*x+a))*((-(1-cos(b*x+a))*((1-cos(b*x+a))^2*csc(b*x+a)^2- 
1)*csc(b*x+a))^(1/2)*sin(b*x+a)+cos(b*x+a)-1))*(1-cos(b*x+a))^2*csc(b*x+a) 
^2-2*(-(1-cos(b*x+a))*((1-cos(b*x+a))^2*csc(b*x+a)^2-1)*csc(b*x+a))^(1/2)) 
/((1-cos(b*x+a))^2*csc(b*x+a)^2-1)^2/(-(1-cos(b*x+a))*((1-cos(b*x+a))^2*cs 
c(b*x+a)^2-1)*csc(b*x+a))^(1/2)*csc(b*x+a)
 
3.4.2.5 Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.40 (sec) , antiderivative size = 803, normalized size of antiderivative = 4.00 \[ \int \frac {\cos ^{\frac {5}{2}}(a+b x)}{\sin ^{\frac {5}{2}}(a+b x)} \, dx=\text {Too large to display} \]

input
integrate(cos(b*x+a)^(5/2)/sin(b*x+a)^(5/2),x, algorithm="fricas")
 
output
-1/24*(3*(-I*b*cos(b*x + a)^2 + I*b)*(-1/b^4)^(1/4)*log(2*b^2*sqrt(-1/b^4) 
*cos(b*x + a)*sin(b*x + a) + 2*cos(b*x + a)^2 - 2*(I*b^3*(-1/b^4)^(3/4)*co 
s(b*x + a) - I*b*(-1/b^4)^(1/4)*sin(b*x + a))*sqrt(cos(b*x + a))*sqrt(sin( 
b*x + a)) - 1) + 3*(I*b*cos(b*x + a)^2 - I*b)*(-1/b^4)^(1/4)*log(2*b^2*sqr 
t(-1/b^4)*cos(b*x + a)*sin(b*x + a) + 2*cos(b*x + a)^2 - 2*(-I*b^3*(-1/b^4 
)^(3/4)*cos(b*x + a) + I*b*(-1/b^4)^(1/4)*sin(b*x + a))*sqrt(cos(b*x + a)) 
*sqrt(sin(b*x + a)) - 1) - 3*(b*cos(b*x + a)^2 - b)*(-1/b^4)^(1/4)*log(-2* 
b^2*sqrt(-1/b^4)*cos(b*x + a)*sin(b*x + a) + 2*cos(b*x + a)^2 + 2*(b^3*(-1 
/b^4)^(3/4)*cos(b*x + a) + b*(-1/b^4)^(1/4)*sin(b*x + a))*sqrt(cos(b*x + a 
))*sqrt(sin(b*x + a)) - 1) + 3*(b*cos(b*x + a)^2 - b)*(-1/b^4)^(1/4)*log(- 
2*b^2*sqrt(-1/b^4)*cos(b*x + a)*sin(b*x + a) + 2*cos(b*x + a)^2 - 2*(b^3*( 
-1/b^4)^(3/4)*cos(b*x + a) + b*(-1/b^4)^(1/4)*sin(b*x + a))*sqrt(cos(b*x + 
 a))*sqrt(sin(b*x + a)) - 1) + 3*(b*cos(b*x + a)^2 - b)*(-1/b^4)^(1/4)*log 
(2*(b^3*(-1/b^4)^(3/4)*cos(b*x + a) - b*(-1/b^4)^(1/4)*sin(b*x + a))*sqrt( 
cos(b*x + a))*sqrt(sin(b*x + a)) - 1) - 3*(b*cos(b*x + a)^2 - b)*(-1/b^4)^ 
(1/4)*log(-2*(b^3*(-1/b^4)^(3/4)*cos(b*x + a) - b*(-1/b^4)^(1/4)*sin(b*x + 
 a))*sqrt(cos(b*x + a))*sqrt(sin(b*x + a)) - 1) + 3*(I*b*cos(b*x + a)^2 - 
I*b)*(-1/b^4)^(1/4)*log(-2*(I*b^3*(-1/b^4)^(3/4)*cos(b*x + a) + I*b*(-1/b^ 
4)^(1/4)*sin(b*x + a))*sqrt(cos(b*x + a))*sqrt(sin(b*x + a)) - 1) + 3*(-I* 
b*cos(b*x + a)^2 + I*b)*(-1/b^4)^(1/4)*log(-2*(-I*b^3*(-1/b^4)^(3/4)*co...
 
3.4.2.6 Sympy [F(-1)]

Timed out. \[ \int \frac {\cos ^{\frac {5}{2}}(a+b x)}{\sin ^{\frac {5}{2}}(a+b x)} \, dx=\text {Timed out} \]

input
integrate(cos(b*x+a)**(5/2)/sin(b*x+a)**(5/2),x)
 
output
Timed out
 
3.4.2.7 Maxima [F]

\[ \int \frac {\cos ^{\frac {5}{2}}(a+b x)}{\sin ^{\frac {5}{2}}(a+b x)} \, dx=\int { \frac {\cos \left (b x + a\right )^{\frac {5}{2}}}{\sin \left (b x + a\right )^{\frac {5}{2}}} \,d x } \]

input
integrate(cos(b*x+a)^(5/2)/sin(b*x+a)^(5/2),x, algorithm="maxima")
 
output
integrate(cos(b*x + a)^(5/2)/sin(b*x + a)^(5/2), x)
 
3.4.2.8 Giac [F]

\[ \int \frac {\cos ^{\frac {5}{2}}(a+b x)}{\sin ^{\frac {5}{2}}(a+b x)} \, dx=\int { \frac {\cos \left (b x + a\right )^{\frac {5}{2}}}{\sin \left (b x + a\right )^{\frac {5}{2}}} \,d x } \]

input
integrate(cos(b*x+a)^(5/2)/sin(b*x+a)^(5/2),x, algorithm="giac")
 
output
integrate(cos(b*x + a)^(5/2)/sin(b*x + a)^(5/2), x)
 
3.4.2.9 Mupad [B] (verification not implemented)

Time = 1.78 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.22 \[ \int \frac {\cos ^{\frac {5}{2}}(a+b x)}{\sin ^{\frac {5}{2}}(a+b x)} \, dx=-\frac {2\,{\cos \left (a+b\,x\right )}^{7/2}\,{\left ({\sin \left (a+b\,x\right )}^2\right )}^{3/4}\,{{}}_2{\mathrm {F}}_1\left (\frac {7}{4},\frac {7}{4};\ \frac {11}{4};\ {\cos \left (a+b\,x\right )}^2\right )}{7\,b\,{\sin \left (a+b\,x\right )}^{3/2}} \]

input
int(cos(a + b*x)^(5/2)/sin(a + b*x)^(5/2),x)
 
output
-(2*cos(a + b*x)^(7/2)*(sin(a + b*x)^2)^(3/4)*hypergeom([7/4, 7/4], 11/4, 
cos(a + b*x)^2))/(7*b*sin(a + b*x)^(3/2))